Re: [xsl] An (almost) identity stylesheet

Subject: Re: [xsl] An (almost) identity stylesheet
From: "bryan rasmussen" <rasmussen.bryan@xxxxxxxxx>
Date: Thu, 10 Apr 2008 10:46:00 +0200
think it should be like this you're looking for.


<xsl:template match="*">
<xsl:copy><xsl:apply-templates select="@*"/><xsl:apply-templates/></xsl:copy>
</xsl:template>
<xsl:template match="@*">
<xsl:copy/>
</xsl:template>
<xsl:template match="@attrib2">
<xsl:attribute name="@attrib2">0</xsl:attribute>
</xsl:template>

cheers,
Bryan Rasmussen
On Thu, Apr 10, 2008 at 10:40 AM, Karol Krenski <mimooh@xxxxxxxxxxxxxxx> wrote:
> Hi list,
>
>  I am a novice to XSLT, learned mainly form online tutorials. This XSLT
>  thing is killing me. Can't figure out how to transform my doc.xml:
>
>  <?xml version="1.0" encoding="UTF-8"?>
>  <foo>
>     <bar>
>         <date attrib1='aaaaaaa' attrib2='bbbbbb'>25-02-08</date>
>                                          ^
>         <name attrib3='null'>AAAAAAAAAAAAAAA</name>
>     </bar>
>     <bar>
>         <date attrib1='cccccc' attrib2='dddddd'>26-02-08</date>
>                                         ^
>         <name attrib4='null'>BBBBBBBBBBBBBBB</name>
>     </bar>
>  </foo>
>
>
>  into
>
>
>  <?xml version="1.0" encoding="UTF-8"?>
>  <foo>
>     <bar>
>         <date attrib1='aaaaaaa' attrib2='0'>25-02-08</date>
>                                          ^
>         <name attrib3='null'>AAAAAAAAAAAAAAA</name>
>     </bar>
>     <bar>
>         <date attrib1='cccccc' attrib2='0'>26-02-08</date>
>                                         ^
>         <name attrib4='null'>BBBBBBBBBBBBBBB</name>
>     </bar>
>  </foo>
>
>  Can somebody please suggest the correct stylesheet?
>
>  I am blindly typing mainly 'copy' or 'copy-of' in my templates and the
>  output generation mechanics make little sense to me. The docs, comparing
>  to other programing documentation seems hard to understand. Could
>  somebody suggest good docs, please?
>
>  Regards,
>  Karol

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