Re: [xsl] Extracting value from node with formatter elements

["Vyacheslav Sedov" <vyacheslav.sedov@xxxxxxxxx>]

use <xsl:copy-of select="."/>

On Mon, Apr 14, 2008 at 5:22 PM, Amit Hanchinamani
<a.hanchinamani@xxxxxxxxxxx> wrote:
> Hi All,
>
>  I am using XSLT 2.0 and parser Saxon.
>
>  I am transforming some html tags to another tag format. I have span tags
> which contain text value surrounded by formattere like bold, italic and
> underline. The problem is when I try to extract the value of the node, it
> always returns the text value without formatters <b>,<u> & <i>. The
> following is the code:
>
>  <xsl:template match="span" mode="copy">
>        <xsl:variable name="elementText">
> <xsl:value-of select="." />
>        </xsl:variable>
>
>  The input tag looks the following
>  <span style="font-family:Times New Roman;font-size:12.0pt;"><b><u>blah
> blah</u></b></span>
>
>  I want to get the entire node value "<b><u>blah blah</u></b>". But using
> <xsl:value-of select="." /> or <xsl:value-of select="text()"/> or
> <xsl:value-of select="current()" /> returns only "blah blah". I cannot
> figure out how to get the entire value along with the formatting tags.
>  Any help appreciated.
>
>  Regards,
>  Amit
>
>
>  .