Re: [xsl] Nesting XPath predicates

Subject: Re: [xsl] Nesting XPath predicates
From: Florent Georges <lists@xxxxxxxxxxxx>
Date: Fri, 25 Apr 2008 11:31:47 +0200 (CEST)
Liam Quin wrote:

  Hi

> > //service[@name = current()/serviceName]

> That will work in the given example, but stops working if
> you put that line inside a for-each...  or more precisely
> works differently :-)

  Yes.  It will "work differently," exactly the same way your variable
will "work differently" if you put it in a for-each ;-)

  Regards,

--drkm























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