Re: [xsl] Conditional String Substitution

Subject: Re: [xsl] Conditional String Substitution
From: Nathan Potter <ndp@xxxxxxxxxxxxxxxxxxxx>
Date: Fri, 25 Apr 2008 21:15:17 -0700
On Apr 25, 2008, at 11:46 AM, Dimitre Novatchev wrote:

I need to look at the value of the attribute "href" and determine if it ends
in the suffix ".xml"


If so then I need to replace the ".xml" suffix with a ".html" suffix.

I got it to work using a pretty convoluted set of XPath expressions in
conjunction with xsl:if but I think that I am missing something...

This can be accomplished with a single XPath 1.0 expression:


concat(substring(@x,
	         1,
	         string-length(@x)
	          -4
	         *
	          (substring(@x, string-length(@x)-3) = '.xml')
	        ),

substring('.html',
1
div
(substring(@x, string-length(@x)-3) = '.xml')
)
)



I picked the first parameter of the concat apart and I understand how it works.



When I try to isolate the second parameter:



substring('.html',1 div(substring(@href, string-length(@href)-3) = '.xml'))



My transformer won't parse it. Oddly, it works fine when imbedded in your example.


Can you explain how it works?



Thanks,


N








--
Cheers,
Dimitre Novatchev
---------------------------------------
Truly great madness cannot be achieved without significant intelligence.
---------------------------------------
To invent, you need a good imagination and a pile of junk
-------------------------------------
Never fight an inanimate object
-------------------------------------
You've achieved success in your field when you don't know whether what
you're doing is work or play




On Fri, Apr 25, 2008 at 10:22 AM, Nathan Potter
<ndp@xxxxxxxxxxxxxxxxxxxx> wrote:


Greetings,

I need to do some string manipulation of an attribute value using XSLT.

I need to look at the value of the attribute "href" and determine if it ends
in the suffix ".xml"


If so then I need to replace the ".xml" suffix with a ".html" suffix.

I got it to work using a pretty convoluted set of XPath expressions in
conjunction with xsl:if but I think that I am missing something...


Is there a more straight forward way of accomplishing this?


Example(s):


<xsl:template match="thredds:catalogRef">

       <xsl:variable name="href" select="./@xlink:href" />
       <xsl:variable name="linkSuffix"
select="substring($href,string-length($href) - 3)" />
       <xsl:variable name="linkBody"
select="substring($href,1,string-length($href) - 4)" />

<xsl:if test="$linkSuffix='.xml'">
<xsl:value-of select="$indent"/><a
href="{concat($linkBody,'.html')}" ><xsl:value-of select="./ @xlink:title"/>
/</a>
</xsl:if>


<xsl:if test="not($linkSuffix='.xml')">
<xsl:value-of select="$indent"/><a href="{$href}" ><xsl:value-of
select="./@xlink:title"/> /</a>
</xsl:if>


</xsl:template>



I used a bunch of variables in the example simply to make it more readable,
the example could be condensed to:


<xsl:template match="thredds:catalogRef">

<xsl:if test="substring(./@xlink:href,string-length(./ @xlink:href) -
3)='.xml'">
<a
href="{concat(substring(./@xlink:href,1,string-length(./ @xlink:href) -
4),'.html')}" ><xsl:value-of select="./@xlink:title"/> /</a>
</xsl:if>


<xsl:if
test="not(substring(./@xlink:href,string-length(./@xlink:href) - 3))">
<a href="{./@xlink:href}" ><xsl:value-of
select="./@xlink:title"/> /</a>
</xsl:if>
<br/>


</xsl:template>

Thanks!

Nathan






============================================================ Nathan Potter Oregon State University, COAS ndp at coas.oregonstate.edu 104 Ocean. Admin. Bldg. 541 737 2293 voice Corvallis, OR 97331-5503 541 737 2064 fax


============================================================ Nathan Potter Oregon State University, COAS ndp at coas.oregonstate.edu 104 Ocean. Admin. Bldg. 541 737 2293 voice Corvallis, OR 97331-5503 541 737 2064 fax

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