Subject: Re: [xsl] Using xsl:variable and replace() to remove specific characters. From: David Carlisle <davidc@xxxxxxxxx> Date: Tue, 29 Apr 2008 12:26:17 +0100 |
> held in the <ext-link> elements are > stripped out. This means that semi-colons, commas and other punctuation is > then left behind and this looks especially bad If you only want to lose punctuation that was by one of those elements, just do so. <xsl:template match="text()[preceding-sibling::*[1][self::ext-link]]"> <xsl:value-of select="replace(.,'[,;]\s*$','')"/> </xsl:template> <xsl:template match="text()[preceding-sibling::*[1][self::ext-link]]"> <xsl:value-of select="replace(.,'^\s*[,;]','')"/> </xsl:template> which, If I got that right, just removes ' and ; (and following white space) from the end of a text node that's followed by ext-link and similarly zaps punctuation from the start of text nodes that folloe ext-link. David ________________________________________________________________________ The Numerical Algorithms Group Ltd is a company registered in England and Wales with company number 1249803. The registered office is: Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom. This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. ________________________________________________________________________
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