[xsl] method transform (JAXP)

Subject: [xsl] method transform (JAXP)
From: IZASKUN GUTIERREZ GUTIERREZ <igutierrez027@xxxxxxxxxxxxx>
Date: Thu, 8 May 2008 10:49:24 +0200
Hello everybody!

I am using JAXP to execute templates.In the method transformer.transform , the

second parameter is one StreamResult. I can obtain the result in a File like


File output = new File ("C:/Users/Izaskun/Desktop/workspace5/modelo/mayo.txt");
transformer.transform(new StreamSource(sourceId), new StreamResult(output));

I need to obtain the result in a var String because the result is only one line

and I dont know how to do it, because I tried a lot of forms but I dont obtain


Could anybody help me?



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