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Subject: Re: [xsl] Finding Nodes That Match Distinct Node Value From: "Darcy Parker" <darcyparker@xxxxxxxxx> Date: Thu, 8 May 2008 12:18:55 -0400 |
I keep forgetting about an XSLT function called current(). <xsl:for-each select="//Artist[@festival = current()]"> will also work. If you use current(), you don't have to create <xsl:variable name="CurrentFestival" select="."/> Darcy On Thu, May 8, 2008 at 12:10 PM, Darcy Parker <darcyparker@xxxxxxxxx> wrote: > Hi Trish, > > > The issue is a context issue. When you write: > <xsl:for-each select="//Artist[@festival = .]"> > the '.' inside the predicate refers to the Artist node being being > filtered with the predicate. > You need to save the current Festival in a variable and use this. > > A simplified version of the template that does what I think you want: > > > <?xml version="1.0" encoding="utf-8"?> > <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";> > > <xsl:template match="/"> > > <xsl:for-each select="//Artist/@festival[not(.=preceding::Artist/@festival)]"> > <xsl:value-of select="concat('Festival=',.,'
')"/> > <xsl:variable name="CurrentFestival" select="."/> > <xsl:for-each select="//Artist[@festival = $CurrentFestival]"> > <xsl:value-of select="concat(' Artist=',@name,' Date=',Date,' > Stage=',Stage,'
')"/> > > </xsl:for-each> > </xsl:for-each> > </xsl:template> > </xsl:stylesheet> > > Output is: > Festival=2007 > Artist=John Doe Date=08/17/07 Stage=Stage Two > Artist=Jane Doe Date=08/15/07 Stage=Stage Three > Artist=Dick Doe Date=08/16/07 Stage=Stage One > Festival=2006 > Artist=Sally Doe Date=08/16/06 Stage=Stage Four > Artist=John Q. Public Date=08/15/06 Stage=Stage One > Festival=2005 > Artist=John Smith Date=08/17/05 Stage=Stage Three > Festival=2004 > Artist=Jane Smith Date=08/17/04 Stage=Stage Four > Artist=Sally Smith Date=08/16/04 Stage=Somethin' Else > Artist=Dick Smith Date=08/16/04 Stage=Stage Two > > > > On Thu, May 8, 2008 at 11:50 AM, <Trish@xxxxxxxxxxxxxx> wrote: > > Hi: > > > > I want to loop through an xml document and get distinct values from an > > attribute and then find all sibling nodes that have that attribute > > value. > > > > I'm pulling distinct festivals based on @festival within each artist > > just fine, but then I want to go back and get all of the Artist info per > > festival. It seems like the code I'm using to do this should work, but > > it doesn't. I can't change the organization of the xml. I'm trying not > > to use keys. I only have access to XSL 1.0 for this project. The line I > > need help with is: > > <xsl:for-each select="//Artist[@festival = .]"> > > > > I'm guessing that the value of "." is lost because I'm beginning at the > > top of the document again. I'm certain that one of you has an elegant > > solution. > > > > XML fragment (url's removed on purpose): > > > > <?xml version="1.0" encoding="utf-8" ?> > > <Festival> > > <Artist festival="2007" name="John Doe"> > > <Url>http://...</Url> > > <Date>08/17/07</Date> > > <Stage>Stage Two</Stage> > > </Artist> > > <Artist festival="2007" name="Jane Doe"> > > <Url>http://...</Url> > > <Date>08/15/07</Date> > > <Stage>Stage Three</Stage> > > </Artist> > > <Artist festival="2007" name="Dick Doe"> > > <Url>http://...</Url> > > <Date>08/16/07</Date> > > <Stage>Stage One</Stage> > > </Artist> > > <Artist festival="2006" name="Sally Doe"> > > <Url>http://...</Url> > > <Date>08/16/06</Date> > > <Stage>Stage Four</Stage> > > </Artist> > > <Artist festival="2006" name="John Q. Public"> > > <Url>http://...</Url> > > <Date>08/15/06</Date> > > <Stage>Stage One</Stage> > > </Artist> > > <Artist festival="2005" name="John Smith"> > > <Url>http://...</Url> > > <Date>08/17/05</Date> > > <Stage>Stage Three</Stage> > > </Artist> > > <Artist festival="2004" name="Jane Smith"> > > <Url>http://...</Url> > > <Date>08/17/04</Date> > > <Stage>Stage Four</Stage> > > </Artist> > > <Artist festival="2004" name="Sally Smith"> > > <Url>http://...</Url> > > <Date>08/16/04</Date> > > <Stage>Somethin' Else</Stage> > > </Artist> > > <Artist festival="2004" name="Dick Smith"> > > <Url>http://...</Url> > > <Date>08/16/04</Date> > > <Stage>Stage Two</Stage> > > </Artist> > > </Festival> > > > > Code Excerpt: > > > > <table align="center" border="0" cellpadding="3" cellspacing="1"> > > <tr align="left" valign="top"> > > <td>artist</td> > > <td>date</td> > > <td>stage</td> > > </tr> > > <xsl:for-each > > select="//Artist/@festival[not(.=preceding::Artist/@festival)]"> > > <tr> > > <td colspan="3"> > > <a name="{.}"></a> > > <xsl:choose> > > <xsl:when test=". = '2007'"> > > 2 0 0 7 • <a href="#2006">2 0 0 > > 6</a> • <a href="#2005">2 0 0 5</a> • <a > > href="#2004">2 0 0 4</a><br /> > > </xsl:when> > > <xsl:when test=". = '2006'"> > > <a href="#2007">2 0 0 7</a> • 2 0 0 > > 6 • <a href="#2005">2 0 0 5</a> • <a > > href="#2004">2 0 0 4</a><br /> > > </xsl:when> > > <xsl:when test=". = '2005'"> > > <a href="#2007">2 0 0 7</a> • <a > > href="#2006">2 0 0 6</a> • 2 0 0 5 • <a > > href="#2004">2 0 0 4</a><br /> > > </xsl:when> > > <xsl:when test=". = '2004'"> > > <a href="#2007">2 0 0 7</a> • <a > > href="#2006">2 0 0 6</a> • <a href="#2005">2 0 0 > > 5</a> • 2 0 0 4<br /> > > </xsl:when> > > <xsl:otherwise> > > <a href="#2007">2 0 0 7</a> • <a > > href="#2006">2 0 0 6</a> • <a href="#2005">2 0 0 > > 5</a> • <a href="#2004">2 0 0 4</a><br /> > > </xsl:otherwise> > > </xsl:choose> > > </td> > > </tr> > > <xsl:for-each select="//Artist[@festival = .]"> > > <tr> > > <td><a href="{Url}"><xsl:value-of select="@name" /></a></td> > > <td><xsl:value-of select="Date" /></td> > > <td><xsl:value-of select="Stage" /></td> > > </tr> > > </xsl:for-each> > > </xsl:for-each> > > </table> > > > > Thank you so much in advance, > > Trish
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