Re: [xsl] XSL/XPath to generate a list of ancestors?

[Nathan Potter <ndp@xxxxxxxxxxxxxxxxxxxx>]

On May 12, 2008, at 10:15 AM, Martin Honnen wrote:

> Nathan Potter wrote:
> > On May 12, 2008, at 10:05 AM, Martin Honnen wrote:
> > > Nathan Potter wrote:
> > >
> > > > I tried this:
> > > >      <xsl:template match="*" name="fullNameWorker" mode="fullName">
> > > >         <xsl:if test="generate-id(.)!=generate-id(/)">
> > >
> > > You have a template for element nodes (match="*") so why do you test
> > >   generate-id(.) != generate-id(/)
> > > ? An element (.) is never a root node (/).
> > Because the template recursively ascends the document I need to  
> > test that I have arrived at the top.
>
> But your template with match="*" is never processed for the root  
> node which is match="/". If anything makes sense then
>   generate-id(.) != generate-id(/*)
> as that compares the matched element to the root element (which is  
> different from the root node).

Ahhh! That's it. Since I know what the root element is always a  
myns:Dataset is I can say this:

generate-id(.) != generate-id(/myns:Dataset)


And that stops the recursion problem, and it works.



> --
>
> 	Martin Honnen
> 	http://JavaScript.FAQTs.com/

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Nathan Potter                 Oregon State University, COAS
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