Re: [xsl] Variable containing unique values

Subject: Re: [xsl] Variable containing unique values
From: David Carlisle <davidc@xxxxxxxxx>
Date: Wed, 21 May 2008 15:36:24 +0100
I can't remember if you use xslt 1 or 2, in xslt2 

select="distinct-values(//rolloverDate)" does what you ask.

But assuming you are using xslt 1 then getting unique values is the same
as grouping, and just using one of each group.

select="/rolloverDate[not(preceding::rolloverDate
 

an XML document can only have one top level element so 

/rolloverDate

either matches that element (if the document element is rolloverDate) or
matches nothing. In either case the document eleemnt never has siblins
so the preceding::rolloverDate in the filter will never select anything.


You mean to select the child of the current element, so don't start with
/ which takes you to thetop of the tree:

select="rolloverDate[not(preceding::rolloverDate= current())]"/>


but note this will repeatedly look back over all earlier nodes so can be
quite slow on large sets, hence muenchian grouping.



<xsl:key name="e" match="element" use="rolloverDate"/>
...


	<xsl:variable name="unique-dates">
		<xsl:for-each
		select
="REPORT/Rollover/RolloverForecast/summaryAccount/element[generate-id()=generate-id(key('e',rolloverDate)[1])]">
   <xsl:copy-of select="."/>
	</xsl:for-each>
	</xsl:variable>

David

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