Subject: Re: [xsl] Output sorted XHTML table for a subset of elements From: "Erik Vullings" <erik.vullings@xxxxxxxxx> Date: Sun, 25 May 2008 09:44:41 +0200 |
Hi, I'm not familiar with your XSLT library, but the following XSLT worked for me: <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html" encoding="Windows-1252" /> <xsl:template match="/users"> <html> <body> <table> <tr> <xsl:for-each select="user"> <xsl:sort select="lines" data-type="number" order="descending"/> <xsl:if test = "lines > 25"> <td><xsl:value-of select="@name" />(<xsl:value-of select="lines" />)</td> </xsl:if> </xsl:for-each> </tr> </table> </body> </html> </xsl:template> </xsl:stylesheet> Cheers Erik On Sat, May 24, 2008 at 4:45 PM, Steven Davies <xsl-list@xxxxxxxxxxx> wrote: > Hi, > > I've been having a problem with a stylesheet I'm creating and need some > help with a part of it - given the following XML snippet: > > <users> > <user name="alf"> > <lines>7</lines> > </user> > <user name="bert"> > <lines>78</lines> > </user> > <user name="charlie"> > <lines>731</lines> > </user> > <user name="derek"> > <lines>62</lines> > </user> > </users> > > ..what I'm trying to achieve is an XHTML table with 5 columns and > however many rows are necessary (imagine there may be a hundred or so > users) where the items in the table consist of only the users where the > user's line count is above 25 and is sorted by their line count. > > So for the above snippet the output should be: > > <table> > <tr> > <td>charlie (731)</td> > <td>bert (78)</td> > <td>derek (62)</td> > </tr> > </table> > > ..obviously with more columns per row and more rows depending on the > size of the input document. > > I've tried to do this using a template matching the next-siblings of the > users to achieve the grouping, but then I can't sort the items or select > the ones I want because the XPath works on the input node set and not a > node set I've selected myself (using for-each or a template). > > If it makes any difference I'm using libXSLT 1.1.22 to do the > transformation. > > Can anyone give me any pointers with this? > > Thanks, > Steve
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