Subject: [xsl] Making all attributes empty and retaining the attributes names From: "Pankaj Chaturvedi" <pankaj.chaturvedi@xxxxxxxxx> Date: Fri, 30 May 2008 17:50:52 +0530 |
Hi all, I have strange requirement, where in I need to remove all the attribute values but need to retain their names (basically having empty attributes) along with their elements. I have written a small template to get this done but all the attributes get removed also. <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions"> <xsl:output encoding="UTF-8" indent="yes"/> <xsl:template match="node()"> <xsl:copy> <xsl:apply-templates select="node()"/> </xsl:copy> </xsl:template> <xsl:template match="text()"/> </xsl:stylesheet> I tried to retain the attributes names with something like below but I know its incorrect: <xsl:template match="@*"> <xsl:copy> <xsl:apply-templates select="name(@*)"/> </xsl:copy> </xsl:template> Error: Too many parameters. Other simple way is to use regular expression (search/replace) but would prefer to avoid that. Any ideas please. Best, Pankaj Chaturvedi ============================================================================ ================
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