RE: [xsl] Check the last character (XSLT V 2.0)

Subject: RE: [xsl] Check the last character (XSLT V 2.0)
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Mon, 16 Jun 2008 14:40:25 +0100
Use the XPath 2.0 ends-with() function.

PS: the string "[#x0003F]" might mean "question mark" to you, but that's a
private convention. It doesn't mean that to the rest of us, and it's likely
to confuse everybody if you assume that everyone understands the meaning of
your data.

Michael Kay
http://www.saxonica.com/  

> -----Original Message-----
> From: Pankaj Chaturvedi [mailto:pankaj.chaturvedi@xxxxxxxxx] 
> Sent: 16 June 2008 14:25
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Check the last character (XSLT V 2.0)
> 
> 
> Hi,
> 
> I've snippet of markup which looks like below, wherein I am 
> trying search that the string <articletitle> "ends" with 
> question mark [#x0003F]. 
> 
> XML Snippet
> ===========
> 
> <articletitle>A team production theory of corporate 
> law&quest;</articletitle>
> 
> XSLT
> =====
> 
> <xsl:when test="contains(string(), '[#x0003F]')">
> <!--  Do something  -->
> </xsl:when>
> 
> The above code works perfect for the above snippet, but 
> obviously fails for the below one as it does "contains" 
> "?"/[#x0003F] but not "ends" with it. I was thinking using 
> regular expression to check the last character but thought, 
> taking suggestions to handle it in better way before getting 
> my hands into it.
> 
> 
> <articletitle>This is a sample&quest; Hello world</articletitle>
> 
> 
> Any guidance will be highly appreciated.
> 
> Best,
> 
> Pankaj Chaturvedi
> 
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