Subject: Re: [xsl] Empty input in analyze-string From: "Joe Fawcett" <joefawcett@xxxxxxxxxxx> Date: Fri, 4 Jul 2008 14:30:24 +0100 |
<data> <para>C.1</para> <para>F.1</para> <para></para> <para>H.1</para> <para>F.2</para> </data>
I get (with Saxon 9.1): <output> <input>C.1</input> <match>C.1</match> <input>F.1</input> <match>F.1</match> <input/> <input>H.1</input> <nonmatch>H.1</nonmatch> <input>F.2</input> <match>F.2</match> </output>
Joe http://joe.fawcett.name
-------------------------------------------------- From: "Michael Kay" <mike@xxxxxxxxxxxx> Sent: Friday, July 04, 2008 2:18 PM To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Subject: RE: [xsl] Empty input in analyze-string
It doesn't look to me as if it matches an empty string. Perhaps you are misinterpreting the evidence?
Michael Kay http://www.saxonica.com/
-----Original Message----- From: Mathieu Malaterre [mailto:mathieu.malaterre@xxxxxxxxx] Sent: 04 July 2008 13:44 To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] Empty input in analyze-string
Hello,
I cannot figure out how to tell xsl:analyze-string that empty input should not match regex.
eg.
<xsl:variable name="myregex">^([CF]\.[0-9\.]+)\s*(.*)$</xsl:variable> <xsl:analyze-string select="$para2" regex="{$myregex}"> <xsl:matching-substring> <xsl:value-of select="regex-group(1)"/> </xsl:matching-substring> ...
if para2 is an empty element, then the regex success and return an empty string. How do I express in my regex that empty is a non-matching regex ?
Thanks ! -- Mathieu
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