Subject: Re: [xsl] How to produce X when an attribute of an element does not exist or equals Y? From: Mark Carlson <carlsonm@xxxxxxxxxxxxxxxx> Date: Tue, 8 Jul 2008 20:05:13 -0700 (PDT) |
Hi, I'm new to the listserv and to XSL. Using the XML below and XSLT 1.0, I would like content to appear both when an attribute of an element does not exist and when it equals X. Specifically, I would like the contents of data-field tag 555 to appear if this data-field does not have any "ind1" attribute, or if its ind1 equals 8.
Data fields with indicators versus no indicators in my XML look like this: <data-field tag="555" ind1="0"> <subfield code="a">...</subfield> </data-field> <data-field tag="555"> <subfield code="a">...</subfield> </data-field>
This is the XSLT I have figured out, minus the missing part:
<xsl:if test="data-field[@tag='555'][@ind1='8'] | ...or if a data-field with attribute 555 has no attribute ind1">
<otherfindaid encodinganalog="555">
<xsl:for-each select="data-field[@tag='555'][@ind1='8'] | ...or if a data-field with attribute 555 has no attribute ind1">
<p>
<xsl:value-of select="."/>
</p>
</xsl:for-each>
</otherfindaid>
</xsl:if>
I would be very grateful for any help. Thank you!
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