Subject: Re: [xsl] accessing the input XML's doctype From: David Carlisle <davidc@xxxxxxxxx> Date: Wed, 16 Jul 2008 22:44:58 +0100 |
> But my understanding is that the parser reads in the XML, resolves any > default attribute values, and then passes the document tree to the XSLT > processor. The XSLT processor itself doesn't know or care about the > doctype information. Is this correct? essentially, yes. what I'd do (if you have write access to local copies of the dtds) is to ammend them to default a couple of attributes on to th etop level element which contain the PUBLIC and SYSTEM identifiers. then if you have <!DOCTYPE foo PUBLIC "a//b//b" "dtd/this/that'dtd"> <foo> If you've modified your local copy of the dtd, the paraser can report <foo PUBLIC="a//b//b" SYSTEM="dtd/this/that'dtd"> ... and then picking up the information from xsl is easy. You then want to use the same ids in output. unfortunately you can't use dynamically calculated values with doctype-public on xsl:output, but you can on xsl:result-document, so you just need <xsl:template match="/"> <xsl:result-document href=".." doctype-public="{*/@PUBLIC)" doctype-system="{*/@SYSTEM}"/> If editing the dtd is not an otion for some reason other things can produce the same effect as defaulting the attribtes yu could (I assume, not done it personally) interpose a sax filter between the original source and the xslt engine that just passed everything through except defaulted these attributes. David ________________________________________________________________________ The Numerical Algorithms Group Ltd is a company registered in England and Wales with company number 1249803. The registered office is: Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom. This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. ________________________________________________________________________
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