Re: [xsl] How to I keep attributes names and values in a sort?

["Mark Wilson" <mark@xxxxxxxxxxxx>]

Thank you. Sorry I repeated the post, but I did not receive Martin's earlier 
reply. Appreciate your comments.
REgards,
mark

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From: "Mukul Gandhi" <gandhi.mukul@xxxxxxxxx>
Sent: Sunday, July 20, 2008 9:13 AM
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject: Re: [xsl] How to I keep attributes names and values in a sort?

> On 7/20/08, Mark Wilson <mark@xxxxxxxxxxxx> wrote:
> > When I use
> > the styles sheet in listing 1, I get the concatenated value of the
> > attributes within the start tag, but not the attribute names as in  <Cat
> > 135> instead of <Cat pofis="1" pofis-number="35">.
>
> It's hard to believe that you can get an output like, <Cat 135> from
> the stylesheet. This is not a well-formed XML.
>
> This syntax,
>
> <xsl:template match="*">
>   <xsl:copy>
>      <!-- something here -->
>   </xsl:copy>
> </xsl:template>
>
> would make a shallow copy of the contextual element (i.e., you don't
> get the attributes copied, and the child contents).
>
> To copy attributes as well, you need to do,
>
> <xsl:template match="*">
>   <xsl:copy>
>      <xsl:apply-templates select="@*"/>
>      <!-- something here -->
>   </xsl:copy>
> </xsl:template>
>
> as Martin wrote in an earlier reply.
>
>
> --
> Regards,
> Mukul Gandhi