Subject: Re: [xsl] Is there a way to sometimes bypass a nested for-each group? From: "Mark Wilson" <mark@xxxxxxxxxxxx> Date: Thu, 24 Jul 2008 06:25:23 -0700 |
(2) I implemented your suggestion as: <xsl:for-each-group select="current-group()" group-by="string(SubHeading)"> Is that correct?
This solution would never have occurred to me. So much to learn! Thanks, Mark
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