Re: [xsl] [answered] collecting multiple tokenize() results into one sequence

[Michael Müller-Hillebrand <mmh@xxxxxxxxxxxxx>]

Is praise for XSLT and for the generous specialists on this list on
topic? I hope so...

This mental update to the unlimited power of XSLT 2.0 reminds me, how
difficult/important it is to overcome existing thought patterns. I,
too, would have assumed that the process of grouping divides the
selected sequence into disjunct groups. But no, it does a lot more and
this is described very precisely in the Programmers Reference --
which I know, because I immediately reread the description of xsl:for-
each-group.

Thanks a lot,

- Michael

Am 24.07.2008 um 18:49 schrieb Wendell Piez:

> How about:
>
> <xsl:for-each-group select="//item" group-by="tokenize(meta,',')">
>  <xsl:sort select="current-grouping-key()"/>
>  <h2><xsl:value-of select="current-grouping-key()"/>:</h2>
>  <ul>
>    <xsl:for-each select="current-group()">
>      <xsl:sort select="name"/>
>                   <li>...
>
> Grouping does not require that there be a single grouping key for
> each item grouped, and an item may appear in more than one group.