Subject: Re: [xsl] build-in template question From: Garvin Riensche <g.riensche@xxxxxxx> Date: Fri, 05 Sep 2008 00:42:07 +0200 |
Garvin Riensche wrote, On 2008-09-05 00:17:Hello,During evaluation of applicable templates on a particular node, the most specific template is chosen. If two or more templates is of the same level of specification, then the template with the highest priority is chosen. I have forgotten what happens if two templates cannot be separated (a situaiton that I try to avoid), although a qualified guess is that an XSLT 1.0 processor does something and an XSLT 2.0 processor returns an error message. Anyway, in this case, the match="e" is more specifc than match="text()|@*" so the first template is chosen.
I have a question concerning text nodes. If I have an xml file like
<root> <e>text</e> </root>
and a template like
<xsl:template match="e"> <xsl:copy/> </xsl:template>
than, the output will be "<e>text</e>".
Is the text insterted to the output by xsl:copy or by the build-in template
<xsl:template match="text()|@*"> <xsl:value-of select="."/> </xsl:template> ?
regards, Garvin
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