Re: [xsl] document tree fragments

[David Carlisle <davidc@xxxxxxxxx>]

> Is there a way to use my $thePath variable, instead of including the 
> directory path inside the @filename attribute?

yes:

<docs path="jb">
	<doc filename="wine1.xml" />
	<doc filename="wine2.xml" />
	<doc filename="wine3.xml" />
	...
</docs>





<xsl:template match="docs">
 <xsl:variable name="p" select="document(concat(@path,'/',doc[1]/@filename))"/>
  <xsl:variable name="z" select="document(doc/@filename,$p)"/>
  <xsl:for-each select="$z">
: <xsl:value-of select="."/>
  </xsl:for-each>
</xsl:template>


puts all the document nodes in $z.

> Secondly, I'm not sure I fully understand what my $theWines variable now 
> contains. I believe it is a collection of tree fragments--i.e. there's 
> no single top-most node, is that right? Or is there an implicit / 
> (document) node?


No, ots a set of element nodes, each of which has a (different) root
node (/) as parent.


> The reason I ask is because I have some templates that rely on 
> processing the preceding axis, and whereas my templates work fine for my 
> < wines > xml file, they do not produce the anticipated results when 
> using my $theWines variable.

Yes, nodes in different documents are not related by any axis.


David

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