Subject: Re: [xsl] N input nodes to specific number of ouput nodes From: Colin Paul Adams <colin@xxxxxxxxxxxxxxxxxx> Date: Wed, 22 Oct 2008 16:43:56 +0100 |
>>>>> "Chris" == Bordeman, Chris <Chris.Bordeman@xxxxxxxxxxxxxxxxx> writes: Chris> Hi all. Chris> I need to loop through some nodes and output exactly 10 Chris> output nodes, no matter how many input nodes there are. If Chris> too few input nodes the ouput will just show "N/A" and if Chris> too many input nodes they will just be ignored. Chris> I can do the 'too many' with a for-each and a choose based Chris> on position() but don't get how the 'too few' scenario is Chris> handled. An xsl:choose discriminating on count() should do the trick. -- Colin Adams Preston Lancashire
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