Subject: Re: [xsl] sequence of strings From: Florent Georges <lists@xxxxxxxxxxxx> Date: Tue, 2 Dec 2008 15:12:37 +0100 (CET) |
Ruud Grosmann wrote: Dag Ruud, > My question is: this solution looks clumsy. How can I improve it? I don't have the time to analyze your stylesheet, but a few remarks... It seems you use a string to represent structured values. Why don't you use something structured? In XSLT 2.0, you can pass a sequence of strings like this: <xsl:with-param name="style" select="'italic', 'bold'"/> Unfortunately, you can't have nested sequences, so you can't have something like, say: <!-- Do not try this at home! --> <xsl:with-param name="values" select=" ('style', ('italic', 'bold')), ('key', ('val1', 'val2', ...))"/> But you can use several parameters if suitable: <xsl:with-param name="style" select="'italic', 'bold'"/> <xsl:with-param name="key" select="'val1', 'val2', ..."/> Or you can always use XML: <xsl:with-param name="values"> <style> <italic/> <bold/> </style> <key> <val1/> <val2/> ... </key> </xsl:with-param> Instead of contains(), you will then be able to use regular XPath set operators and mapping techniques: <xsl:template name="get_attributes" as="xs:string?"> <xsl:param name="style" as="xs:string*"/> <xsl:variable name="map"> <i key="bold" name="BLD"/> <i key="italic" name="ITA"/> </xsl:variable> <xsl:sequence select="$map/i[@key = $style][1]/@name"/> </xsl:template> And if you use a function instead of a named template, you can use the following to get the element name (but that's really a matter of taste): my:get-element-name(('bold', 'italic')) Regards, -- Florent Georges http://www.fgeorges.org/
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