Re: [xsl] XPath and namespace nodes: a tough one

[Florent Georges <lists@xxxxxxxxxxxx>]

Andrew Welch wrote:

> let $foo :=   <n0:pdu xmlns:n0="http://a.example";>
>      <n1:elem1 xmlns:n1="http://b.example";>
>          content
>      </n1:elem1>
>   </n0:pdu>
> return $foo/*

> you get:

> <n1:elem1 xmlns:n1="http://b.example";>
>      content
> </n1:elem1>

  Which is not really nice if you have something like:

    <n1:elem1 xmlns:n1="http://b.example"; value="n0:something">
       content
    </n1:elem1>

  BTW, Elliotte said:

> The subdocument with elem1 as its apex node can be extracted from
> this second case with an XPath expression such as:
>  (//. | //@* | //namespace::*)[ancestor-or-self::n1:elem1]

  But this expression returns a node set with several nodes, all
descendant of n1:elem1, and not the element n1:elem1 (with its
descendant.)

  Unfortunately, this is not possible to discard a namespace in
XPath only.

  Regards,

-- 
Florent Georges
http://www.fgeorges.org/