Subject: Re: [xsl] XSLT grouping(?) issue From: "Mukul Gandhi" <gandhi.mukul@xxxxxxxxx> Date: Mon, 22 Dec 2008 16:40:33 +0530 |
Here is a different algorithm, than Mike <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:output method="text" /> <xsl:template match="Orders"> <xsl:for-each-group select="*" group-starting-with="StartOrderGroup"> <xsl:text>
Order
</xsl:text> <xsl:text>-----
</xsl:text> <xsl:variable name="curr-group" select="current-group()" /> <xsl:variable name="indx" select="index-of(for $x in $curr-group return $x/local-name(), 'EndOrderGroup')" /> <xsl:for-each select="$curr-group[position() > 1 and position() < $indx]"> <xsl:value-of select="local-name()" /> - <xsl:value-of select="Id" /><xsl:text>
</xsl:text> </xsl:for-each> </xsl:for-each-group> </xsl:template> </xsl:stylesheet> On Mon, Dec 22, 2008 at 4:07 PM, Fredde Hedberg <syte_orion@xxxxxxxxx> wrote: >> The problem is solvable with XSLT, provided your input XML >> is well >> formed. But your input is not a valid XML document. >> >> for e.g., <Id=1/> is not a valid XML fragment, and >> XML parser >> complains about it. > > My mistake, I apologize. When I simplified my XML I made it more bad formed than it really is... > > <Orders> > <StartOrderGroup> > <Id>1</Id> > </StartOrderGroup> > <Car> > <Id>2</Id> > </Car> > <Car> > <Id>3</Id> > </Car> > <Bus> > <Id>4</Id> > </Bus> > <EndOrderGroup> > <Id>5</Id> > </EndOrderGroup> > <Car> > <Id>6</Id> > </Car> > <Truck> > <Id>7</Id> > </Truck> > <StartOrderGroup> > <Id>8</Id> > </StartOrderGroup> > <Truck> > <Id>9</Id> > </Truck> > <EndOrderGroup> > <Id>10</Id> > </EndOrderGroup> > </Orders> > > That's at least valid XML :) > You've given me hope by saying it is solvable. Will this new XML-fragment allow you to show me how? That would basically save christmas for me... > > Regards > > Fredde -- Regards, Mukul Gandhi
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