Subject: [xsl] Table Span not working From: "V.Ramkumar" <v.ramkumar@xxxxxxxxxxxxxxxxxxxxxx> Date: Tue, 6 Jan 2009 09:17:01 +0530 |
Hi List, I am doing XSL style sheet for XML view. In table, span not able to get, Please correct me any mistake in the below code. XSL ===== The below my code not giving expected result/span in IE. <xsl:template match="thead/row/entry"> <xsl:variable name="colst" select="translate(@namest,'col','')"/> <xsl:variable name="colend" select="translate(@nameend,'col','')"/> <th bgcolor="#C4C4FF" colspan="($colend-$colst)+1"><xsl:apply-templates/></th> </xsl:template> XML ====== Four column table contains a header spanned row like below. <row row-type="straddle-head"> <entry align="center" nameend="col3" namest="col2">PIN-a Δπ (mN/m)</entry> <entry align="center" nameend="col5" namest="col4">PIN-b Δπ (mN/m)</entry> </row> Regards, Ramkumar
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