Subject: Re: [xsl] flattening an xml hierarchy From: "Vasu Chakkera" <vasucv@xxxxxxxxx> Date: Fri, 9 Jan 2009 10:28:57 +0000 |
On 08/01/2009, Evan Lenz <evan@xxxxxxxxxxxx> wrote: > You probably don't want to process attributes of the unwanted elements. > With your code below, an attribute on <Dontwant1> would cause a run-time > error. > > Evan > > Vasu Chakkera wrote: >> USe identity transformation. >> >> <xsl:stylesheet version="1.0" >> xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> >> <xsl:template match="node()|@*"> >> <xsl:copy> >> <xsl:apply-templates select="node()|@*"/> >> </xsl:copy> >> </xsl:template> >> <xsl:template match = "Dontwant1"> >> <xsl:apply-templates select="node()|@*"/> >> </xsl:template> >> <xsl:template match = "dontwant2"/> >> </xsl:stylesheet> >> >> This will do your job. Although.. You have 2 definitions of what you >> want to Remove. >> >> 1. Node and its children >> 2. Node . >> >> I am not sure what you meant by "remove" But anyway, in either case, >> if you want to remove node and all its children, you just define an >> empty template >> if you want to ignore the node alone, then you define the template for >> that node and not bothor about copying the current node, and copy all >> its children. >> >> HTH >> >> 2009/1/8 Tim <timlhunt@xxxxxxxxxxxxxx>: >> >>> Hi, >>> I'd like to remove some elements from an xml hierachy using xslt: >>> >>> Original xml example: >>> <Dontwant1> >>> <dontwant2>foo</dontwant2> >>> <x3> >>> <x4>stuff</x4> >>> <y5>more stuff</y5> >>> </x3> >>> </Dontwant1> >>> >>> Like to have transform output: >>> <x3> >>> <x4>stuff</x4> >>> <y5>more stuff</y5> >>> </x3> >>> >>> Thanks for your insghts. >>> >>> Tim > > -- Vasu Chakkera Numerical Algorithms Group Ltd. Oxford www.vasucv.com
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