Subject: Re: [xsl] read directory and get it as an array|
From: "J. S. Rawat" <jrawat@xxxxxxxxxxxxxx>
Date: Fri, 16 Jan 2009 16:00:33 +0530
document-uri(.)This is what I am trying but not getting the filename!
you may just need the part of that after the last slash, depending on your requirements.