[xsl] Get position of parent

["Philip Vallone" <philip.vallone@xxxxxxxxxxx>]

Hello List,

What is the best way to get the position of a parent node? In the below xml,
assume my context node is para:

/table/tgroup/tbody/row/entry[1]/para

If my context node is para, how do I get the position of its parent entry?

<table frame="all" align="center" id="C-TABLE3" width="90%">
	<title>Title</title>
	<tgroup cols="3">
		<colspec colnum="1" colname="spycolgen1" colwidth="*"/>
		<colspec colnum="2" colname="spycolgen2" colwidth="*"/>
		<colspec colnum="3" colname="spycolgen3" colwidth="*"/>
		<tbody>
			<row>
				<entry>
					<!--get position of parent::entry-->
					<para id="table3-para 1">context
node</para>
				</entry>
				<entry>
					<para>test</para>
				</entry>
				<entry>
					<para>test</para>
				</entry>
			</row>
		</tbody>
	</tgroup>
</table>




Thanks
Phil