Subject: Re: [xsl] xsl:for-each-group and identity transform From: Owen Rees <owen.rees@xxxxxx> Date: Fri, 23 Jan 2009 15:14:19 +0000 |
But this (my) template works:
<xsl:template match="element()|comment()|processing-instruction()" mode="group"> <xsl:copy-of select="current-group()"/> </xsl:template>
-- Owen Rees; speaking personally, and not on behalf of HP. ======================================================== Hewlett-Packard Limited. Registered No: 690597 England Registered Office: Cain Road, Bracknell, Berks RG12 1HN
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