Subject: RE: [xsl] <xsl:number> starting at a preceding-sibling From: Hermann Stamm-Wilbrandt <STAMMW@xxxxxxxxxx> Date: Tue, 27 Jan 2009 09:01:41 +0100 |
> You can handle that by extending the from condition, for example > > from="level1|section". It seems to work as desired only with ' from="root|section" '. While this works for xsltproc (compiled against libxml 20626, libxslt 10117 and libexslt 813) it does not work for xalan-j_2_7_0 -- is that an xalan bug? ============================================================================= ? [xalan-j_2_7_0]$ cat b.xsl <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:output method="xml"/>. <xsl:template match="level1"> <xsl:copy> <xsl:number level="any" from="root|section" format="1"/> </xsl:copy> </xsl:template> <xsl:template match="level2"> <xsl:copy> <xsl:number level="any" from="level1" format="a"/> </xsl:copy> </xsl:template> <xsl:template match="level3"> <xsl:copy> <xsl:number level="any" from="level2" format="i"/> </xsl:copy> </xsl:template> </xsl:stylesheet> [xalan-j_2_7_0]$ cat b.xml <root> <section> <level1></level1> <level1></level1> <level2></level2> <level3></level3> <level2></level2> <level1></level1> <level2></level2> <level3></level3> </section> <section>> <level1></level1> <level1></level1> <level2></level2> <level3></level3> <level2></level2> <level1></level1> <level2></level2> <level3></level3> </section> </root> [xalan-j_2_7_0]$ xsltproc --version Using libxml 20626, libxslt 10117 and libexslt 813 xsltproc was compiled against libxml 20626, libxslt 10117 and libexslt 813 libxslt 10117 was compiled against libxml 20626 libexslt 813 was compiled against libxml 20626 [xalan-j_2_7_0]$ [xalan-j_2_7_0]$ xsltproc b.xsl b.xml <?xml version="1.0"?> <level1>1</level1> <level1>2</level1> <level2>a</level2> <level3>i</level3> <level2>b</level2> <level1>3</level1> <level2>a</level2> <level3>i</level3> <level1>1</level1> <level1>2</level1> <level2>a</level2> <level3>i</level3> <level2>b</level2> <level1>3</level1> <level2>a</level2> <level3>i</level3> [xalan-j_2_7_0]$ java xalan.jar -XSL b.xsl -IN b.xml <?xml version="1.0" encoding="UTF-8"?>. <level1>1</level1> <level1>2</level1> <level2>a</level2> <level3>i</level3> <level2>b</level2> <level1>3</level1> <level2>c</level2> <level3>ii</level3> <level1>1</level1>> <level1>2</level1>> <level2>d</level2>> <level3>iii</level3> <level2>e</level2> <level1>3</level1> <level2>f</level2> <level3>iv</level3>> [xalan-j_2_7_0]$ ============================================================================= ? Hermann Stamm-Wilbrandt Developer, XML Compiler WebSphere DataPower SOA Appliances ---------------------------------------------------------------------- IBM Deutschland Research & Development GmbH Vorsitzender des Aufsichtsrats: Martin Jetter Geschdftsf|hrung: Erich Baier Sitz der Gesellschaft: Bvblingen Registergericht: Amtsgericht Stuttgart, HRB 243294 ----- Forwarded by Hermann Stamm-Wilbrandt/Germany/IBM on 01/27/2009 08:31 AM ----- "Michael Kay" <mike@xxxxxxxxxxx m> To <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> 01/20/2009 09:29 cc AM Subject RE: [xsl] <xsl:number> starting at Please respond to a preceding-sibling xsl-list@xxxxxxxx lberrytech.com You can handle that by extending the from condition, for example from="level1|section". Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Spencer Tickner [mailto:spencertickner@xxxxxxxxx] > Sent: 20 January 2009 00:22 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Re: [xsl] <xsl:number> starting at a preceding-sibling > > Thank you very much for the response Dr. Kay, > > Unfortunately as I expected level="single" and level="any" to > work the same way in regards to from I made my example > document less robust than it probably should have been. With > level="any" the revised xml > source: > > <root> > <section> > <level1></level1> > <level1></level1> > <level2></level2> > <level3></level3> > <level2></level2> > <level1></level1> > <level2></level2> > <level3></level3> > </section> > <section> > <level1></level1> > </section> > </root> > > would come out: > > <root> > <section> > <level1>1</level1> > <level1>2</level1> > <level2>a</level2> > <level3>i</level3> > <level2>b</level2> > <level1>3</level1> > <level2>a</level2> > <level3>i</level3> > </section> > <secton> > <level1>4</level1> > </secton> > </root> > > When the second section should start renumbering itself yet > again to 1 not 4. Once again my apologies for an inadequate test case. > > Spencer > > > On Mon, Jan 19, 2009 at 4:04 PM, Michael Kay > <mike@xxxxxxxxxxxx> wrote: > > Try this: > > > > <xsl:template match="level1"> > > <xsl:copy> > > <xsl:number level="any" from="root" format="1"/> </xsl:copy> > > </xsl:template> > > > > <xsl:template match="level2"> > > <xsl:copy> > > <xsl:number level="any" from="level1" format="a"/> </xsl:copy> > > </xsl:template> > > > > <xsl:template match="level3"> > > <xsl:copy> > > <xsl:number level="any" from="level2" format="i"/> </xsl:copy> > > </xsl:template> > > > > The surprise here (and it took me a while to grasp it) is > that level="any" > > is needed even though you're counting siblings. This is > because the "from" > > pattern doesn't work the way you want it to with level="single". > > > > Michael Kay > > http://www.saxonica.com/ > > > >> -----Original Message----- > >> From: Spencer Tickner [mailto:spencertickner@xxxxxxxxx] > >> Sent: 19 January 2009 23:04 > >> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > >> Subject: [xsl] <xsl:number> starting at a preceding-sibling > >> > >> Hi List and thanks in advance for the help. > >> > >> I'm attempting to number some flat xml using xslt 2.0 and am > >> struggling a bit. Given: > >> > >> <root> > >> <level1></level1> > >> <level1></level1> > >> <level2></level2> > >> <level3></level3> > >> <level2></level2> > >> <level1></level1> > >> <level2></level2> > >> <level3></level3> > >> </root> > >> > >> I need to number each level based on it's preceding-sibling so it > >> would look like: > >> > >> <root> > >> <level1>1</level1> > >> <level1>2</level1> > >> <level2>a</level2> > >> <level3>i</level3> > >> <level2>b</level2> > >> <level1>3</level1> > >> <level2>a</level2> > >> <level3>i</level3> > >> </root> > >> > >> Counting <level1> is easy with <xsl:number> but the template for > >> <level2> and <level3>. Stylesheet is below, template for > >> level3 is ommited as it will hinge on solving the template > for level2 > >> (I know all the variables are pretty ugly): > >> > >> <?xml version='1.0'?> > >> <xsl:stylesheet version="1.0" > >> xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > >> > >> <xsl:template match="/"> > >> <xsl:apply-templates/> > >> </xsl:template> > >> > >> > >> <xsl:template match="*"> > >> <xsl:copy> > >> <xsl:copy-of select="@*"/> > >> <xsl:apply-templates/> > >> </xsl:copy> > >> </xsl:template> > >> > >> <xsl:template match="level1"> > >> <xsl:copy> > >> <xsl:number count="level1" level="single" format="1"/> </xsl:copy> > >> </xsl:template> > >> > >> <xsl:template match="level2"> > >> <xsl:variable name="cousins" select="preceding-sibling::*"/> > >> <xsl:variable name="num"> > >> <xsl:value-of > >> select="count($cousins[last()]/preceding-sibling::*[not(follow > >> ing-sibling::level1)][name() > >> = 'level2'])"/> > >> </xsl:variable> > >> <xsl:variable name="renum"> > >> <xsl:choose> > >> <xsl:when test="$cousins[last()]/name() = > >> name(.)"><xsl:value-of > >> select="number($num) + 2"/></xsl:when> > >> <xsl:otherwise><xsl:value-of > >> select="number($num) + 1"/></xsl:otherwise> > >> </xsl:choose> > >> </xsl:variable> > >> <xsl:copy> > >> <xsl:number value="$renum" format="a"/> > >> </xsl:copy> > >> </xsl:template> > >> > >> </xsl:stylesheet> > >> > >> > >> Any advice would be appreciated. > >> > >> Thanks, > >> > >> Spencer
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