Re: [xsl] Getting nodes where attribute is not in list

Subject: Re: [xsl] Getting nodes where attribute is not in list
From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>
Date: Wed, 25 Feb 2009 10:34:43 -0500
At 2009-02-25 09:29 -0600, Bordeman, Chris wrote:
I need to do something like $items/item[Code not in $codes] where $codes
is a sequence of strings.

$items/item[not(Code = $codes)]


How is this done?

The "=" operator will act on a node set operand by comparing each member of the node set with the other operand. If any of the comparisons are true, the result of the comparison is true. If all of the comparisons are false, the result of the comparison is false.


I hope this helps.

. . . . . . . . Ken

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