RE: [xsl] Getting nodes where attribute is not in list

["Bordeman, Chris" <Chris.Bordeman@xxxxxxxxxxxxxxxxx>]

Thanks very much Ken.


-----Original Message-----
From: G. Ken Holman [mailto:gkholman@xxxxxxxxxxxxxxxxxxxx]
Sent: Wednesday, February 25, 2009 9:35 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Getting nodes where attribute is not in list

At 2009-02-25 09:29 -0600, Bordeman, Chris wrote:
>I need to do something like $items/item[Code not in $codes] where
>$codes is a sequence of strings.

   $items/item[not(Code = $codes)]

>How is this done?

The "=" operator will act on a node set operand by comparing each member
of the node set with the other operand.  If any of the comparisons are
true, the result of the comparison is true.  If all of the comparisons
are false, the result of the comparison is false.

I hope this helps.

. . . . . . . . Ken

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