Subject: [xsl] passing parameters to XSL,what if no value in some cases From: himanshu padmanabhi <himanshu.padmanabhi@xxxxxxxxx> Date: Fri, 6 Mar 2009 14:58:10 +0530 |
First time,code will go to 'else' part,it again returns to this form and 'if' part executes. <CODE> my $parser = XML::LibXML->new(); my $xslt = XML::LibXSLT->new(); my $source = $parser->parse_file($xmlfile); my $style_doc = $parser->parse_file($xslfile); my $stylesheet = $xslt->parse_stylesheet($style_doc); if($in{'flag'} eq "2") { my $results = $stylesheet->transform($source, XML::LibXSLT::xpath_to_string(args => "$in{'args'}",val => "1",new => "$in{'new'}")); print $stylesheet->output_string($results); }else{ my $results = $stylesheet->transform($source, XML::LibXSLT::xpath_to_string(args => "",val => "3",new => "$in{'new'}")); print $stylesheet->output_string($results); } </CODE> 1.In my 'else' above,I don't want to pass 'args'(can I do it?), 2.How can I check in my xsl file whether it is passed or not probably using some 'if' statement or something like this? <CODE> <xsl:choose> <xsl:when test="args_is_given"> <some code> </xsl:when> </xsl:choose> </CODE> ----------------------------- Regards, Himanshu Padmanabhi
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