Subject: RE: [xsl] [xslt] xslt problem From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Thu, 19 Mar 2009 09:00:37 -0000 |
Not the most imaginative title for a post. > > <example> > <someNode> > <value>asas</value> > <name>asas</name> > <space>12</space> > </someNode> > <interestingNode> > <con>someString</con> > <follow> > <node1>1</node1> > <node2>2</node2> > <node3>3</node3> > <node4>4</node4> > </follow> > <space>5</space> > </interestingNode> > </example> > > > Now i want to transform it to: > > <example> > <someNode> > <value>asas</value> > <name>asas</name> > <space>12</space> > </someNode> > <interestingNode> > <con>someString</con> > <follow> > <return>0</return> > </follow> > <space>5</space> > </interestingNode> > > <node1 space="5">1</node1> > <node2 space="5">2</node2> > <node3 space="5">3</node3> > <node4 space="5">4</node4> > </example> > > > The changes are: > - when interestingNode is found, we check the con value > - if con value conforms someString, then we make > transformation of this part by: > - evrything in follow node is moved outside interestingNode > - follow node gets one child return > - all nodes moved outside get an attribute space with > value specified in original node > That seems to be a rule you can translate directly into XSLT: <xsl:template match="interestingNode[con='someString']"> <xsl:copy> <xsl:copy-of select="con"/> <follow><return>0</return></follow> <xsl:copy-of select="space"/> </xsl:copy> <xsl:variable name="space" select="space"/> <xsl:for-each select="follow/*"> <xsl:copy> <xsl:attribute name="space" select="$space"/> <xsl:copy-of select="child::node()"/> </xsl:copy> </xsl:for-each> </xsl:template> Michael Kay http://www.saxonica.com/
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