Subject: Re: [xsl] Interrogating attributes values to get text (part deaux) From: David Carlisle <davidc@xxxxxxxxx> Date: Fri, 20 Mar 2009 13:07:34 GMT |
> The template you wrote always returns the value for the child of the > first <nameloc>. No, it returns the string value of (all) the nmlist child(ren) of the nameloc which has the id specified in the linkend attribute of the current HYPERTEXT. > I need to interrogate each <nameloc> id value to find the one that > matches @linkend for the current <HYPERTEXT>. That's what the code I posted did, using a key lookup. On the xml you posted the template I showed produces this: <?xml version="1.0" encoding="UTF-8"?><step><link item="item1"/></step> which appears to be what you asked for (except that it is well formed) your requested result had an unclosed link element. <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:strip-space elements="*"/> <xsl:template match="/"> <xsl:apply-templates select="document/STEP"/> </xsl:template> <xsl:template match="STEP"> <step><xsl:apply-templates/></step> </xsl:template> <xsl:key name="id" match="nameloc" use="@id"/> <xsl:template match="HYPERTEXT"> <link item="{key('id',@linkend)/nmlist}"/> </xsl:template> </xsl:stylesheet> David ________________________________________________________________________ The Numerical Algorithms Group Ltd is a company registered in England and Wales with company number 1249803. The registered office is: Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom. This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. ________________________________________________________________________
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