Subject: [xsl] Re : [xsl] How to handle dynamic XPath From: Florent Georges <lists@xxxxxxxxxxxx> Date: Sun, 12 Apr 2009 19:52:19 +0000 (GMT) |
fred@xxxxxxxxxxxxx wrote: Hi, > <xsl:with-param name="instance.path" > select="concat($instance.path,'/',$element.prefix,':',@name)" > /> You cannot evaluate an XPath expression supplied as a string in plain XSLT. You can use extensions though for that purpose (of your own or existing one.) I haven't looked deeply into your problem, but I'd say I'd rather user either: 1/ maintaining a pointer in the instance and selecting its correct child(ren) using local-name() and namespace-uri() for each step; 2/ or using a meta-stylesheet: your stylesheet generates another XSLT stylesheet that contains the XPath expressions (you "compile" the schema to the equivalent stylesheet) and you apply this stylesheet to the instance in a second execution. Regards, -- Florent Georges http://www.fgeorges.org/
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] How to handle dynamic XPath, fred | Thread | Re: [xsl] How to handle dynamic XPa, G. Ken Holman |
[xsl] How to handle dynamic XPath, fred | Date | Re: [xsl] How to handle dynamic XPa, G. Ken Holman |
Month |