Subject: Re: [xsl] Count all instances of a named element in a tree From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx> Date: Fri, 29 May 2009 11:53:45 -0400 |
Does anyone know an elegant solution to counting all elements in an XML fragment where the elements to be counted are nested in a tree? An example of the XML is below:
The count in this case would be 8.
T:\ftemp>type charlton.xml <xmltree> <countmein>Node1</countmein> <nodes> <node> <countmein>Node2</countmein> <level>1</level> <nodes> <node> <countmein>Node3</countmein> <level>2</level> <nodes> <node> <countmein>Node4</countmein> <level>3</level> <nodes/> </node> </nodes> </node> <node> <countmein>Node5</countmein> <level>2</level> <nodes/> </node> <node> <countmein>Node6</countmein> <level>2</level> <nodes/> </node> </nodes> </node> <node> <countmein>Node7</countmein> <level>1</level> <nodes> <node> <countmein>Node8</countmein> <level>2</level> <nodes/> </node> </nodes> </node> </nodes> </xmltree>
T:\ftemp>call xslt charlton.xml charlton.xsl 8 T:\ftemp>type charlton.xsl <?xml version="1.0" encoding="US-ASCII"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:template match="/"> <xsl:value-of select="count(//countmein)"/> </xsl:template>
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