Subject: [xsl] Re: Determining whether no single instance of a specific node exists From: Mark Peters <markpeters.work@xxxxxxxxx> Date: Thu, 4 Jun 2009 14:27:31 -0400 |
Sorry, my XSL examples weren't quite right. I'm trying to determine whether no instance of <c/> exists for each <b/> set. So, in my XSL document, assume I'm processing each <a/> node. 1, <xsl:when test="not(b/c)"> 2. <xsl:when test="count(not(b/c)) >= 1"> Thanks, Mark On Thu, Jun 4, 2009 at 2:20 PM, Mark Peters <markpeters.work@xxxxxxxxx> wrote: > Hi Everyone, > > I have the following XML document: > > <a> > <b/> > <b/> > <b/> > </a> > <a> > <b/> > <b/> > <b> > <c/> > </b> > > </a> > <a> > <b/> > <b/> > <b/> > </a> > > For each <b/> set, I want to apply a transformation only if no single > instance of <c/> exists. I know how to check whether a node does > exist, but not how to check whether no single instance of the node > exists. > > I've tried the following conditional statements without success: > > 1, > <xsl:when test="not(a/b/c)"> > > 2. > <xsl:when test="count(not(a/b/c)) >= 1"> > > > What conditional statement should I use? > > Thanks in advance for any help. > > Mark
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