Re: [xsl] Using outer context node inside for-each

Subject: Re: [xsl] Using outer context node inside for-each
From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>
Date: Wed, 08 Jul 2009 13:42:59 -0400
At 2009-07-08 18:31 +0100, Richard Lewis wrote:
Hi there,

Here is an abstraction of my problem template:

 <xsl:template match="record">
   <xsl:param name="show-fields" />
   <xsl:variable name="this" select="." />

<xsl:for-each select="str:tokenize($show-fields)">
<xsl:message><xsl:value-of select="$this/field[@name=.]" /></xsl:message>

Inside the predicate "." refers to the node found by the node test.


You want [@name=current()] to address the context item that is at the start of the XPath expression.

Though I see Martin has taken the problem away with a more compact solution ... still, you wanted to know why yours wasn't working.

I hope this helps.

. . . . . . . . Ken


-- Possible July/August XSLT/XQuery/XSL-FO training in Oakland/CA/USA Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/ Training tools: Comprehensive interactive XSLT/XPath 1.0/2.0 video Video lesson: http://www.youtube.com/watch?v=PrNjJCh7Ppg&fmt=18 Video overview: http://www.youtube.com/watch?v=VTiodiij6gE&fmt=18 G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx Male Cancer Awareness Nov'07 http://www.CraneSoftwrights.com/s/bc Legal business disclaimers: http://www.CraneSoftwrights.com/legal

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