Re: [xsl] Using outer context node inside for-each

[Richard Lewis <richard.lewis@xxxxxxxxxx>]

At Wed, 08 Jul 2009 13:42:59 -0400,
G. Ken Holman wrote:
> 
> At 2009-07-08 18:31 +0100, Richard Lewis wrote:
> >Hi there,
> >
> >Here is an abstraction of my problem template:
> >
> >  <xsl:template match="record">
> >    <xsl:param name="show-fields" />
> >    <xsl:variable name="this" select="." />
> >
> >    <xsl:for-each select="str:tokenize($show-fields)">
> >      <xsl:message><xsl:value-of select="$this/field[@name=.]" 
> > /></xsl:message>
> 
> Inside the predicate "." refers to the node found by the node test.
> 
> You want [@name=current()] to address the context item that is at the 
> start of the XPath expression.
> 
> Though I see Martin has taken the problem away with a more compact 
> solution ... still, you wanted to know why yours wasn't working.
> 
> I hope this helps.
> 
Excellent. Works great. Thanks very much for your help.
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Richard Lewis
ISMS, Computing
Goldsmiths, University of London
Tel: +44 (0)20 7078 5134
Skype: richardjlewis
JID: ironchicken@xxxxxxxxxxxxxxx
http://www.richard-lewis.me.uk/
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