Subject: Re: [xsl] for-each-group for multiple nodes From: Michael Ludwig <mlu@xxxxxxxxxxxxx> Date: Fri, 17 Jul 2009 12:05:45 +0200 |
I am not able to achieve my expected output through for-each-group for multiple nodes in a single template match. Please look into my detailed inputs and find mistakes in my below code.
You increase the chance of getting a useful reply by adhering more strictly to the list guidelines (available online) in that you strip from your input (and output, of course) any complexity it has in terms of text or structure, so that it is, in fact, less detailed.
People looking at your data and code will then not to have to parse lots of information that is totally unrelated to the problem at hand.
Last not least, simplifying your problem may also help you find the solution yourself.
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