Re: [xsl] Getting sibling nodes from unique values

[Mike Ferrari <mikeferrari8@xxxxxxxxx>]

Sweet!
That will teach me to stop overcomplicating things!

Thanks a TON!!


This is the xsl that i ended up with...

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="2.0">
    <xsl:output method="xml"/>
    <xsl:template match="/">
            <xsl:for-each-group select="Root/row" group-by="company">
                <xsl:result-document href="{current-grouping-key()}.xml">
                    <Root>
                        <xsl:copy-of select="current-group()"/>
                    </Root>
                </xsl:result-document>
            </xsl:for-each-group>
    </xsl:template>
</xsl:stylesheet>



On Tue, Aug 4, 2009 at 10:27 AM, Martin Honnen<Martin.Honnen@xxxxxx> wrote:
> Mike Ferrari wrote:
>
>> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>> version="2.0">
>>    <xsl:output method="text"/>
>>    <xsl:template match="/">
>>        <xsl:for-each select="distinct-values(//company)">
>
> Use
>     <xsl:for-each-group select="Root/row" group-by="company">
>        <xsl:result-document href="{current-grouping-key()}.xml">
>          <Root>
>            <xsl:copy-of select="current-group()"/>
>          </Root>
>        </xsl:result-document>
>     </xsl:for-each-group>
>
>
>
>
> --
>
>        Martin Honnen
>        http://msmvps.com/blogs/martin_honnen/
>
>



--
/dev/mike0

http://www.mikeferrari.com