Re: [xsl] How to select for ' in XPATH?

["G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>]

At 2009-08-05 20:36 +0200, Hermann Stamm-Wilbrandt wrote:
> There was a typo in my last email, '%22' works for "
> "/*/*/*[contains(normalize-space(.),'%22')])"
> and '%27' does not work for '
> ( the %22 gets converted to " character by unescape(s) )

This is not true for XPath.  The "%" notation is not recognized.

> > you are left with breaking up the string into components that
> > contain no single quote and components that contain a single quote and
> > then concatenate them e.g. if the selection on the page is e.g.
> > What's that?
> > you use
> > "//*[contains(., concat('What', \"'\", ' that?')"
>
> Good idea to break this up and concatenate.
> But the basic problem remains, how to match for the single " ?
>
> \"'\" does not work :-(

In XSLT 2:

  "//*[contains(., concat('What','''',' that?'))]"

 or more simply just:

  "//*[contains(., 'What'' that?')]"

In XSLT 1:

  "//*[contains(., 'What' that?)]"

But be careful because the above selects the document element which 
will contain all text in its value.

> > Implementing breaking up the string with JavaScript should be possible
> >although having to stuff all that into a bookmarklet might get ugly.
> Perhaps this might get ugly, but not without a solution to match for
> the single " character ...

" is " - the double quote

' is ' - the apostrophe (single quote)

I hope this helps.

. . . . . . . . . . . . . Ken


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