Re: [xsl] Getting the name the input data document

[Jingjun Long <longjingjun@xxxxxxxxx>]

Hello,

I tried to use base-uri to get XML path and static-base-uri to get XSL
path. This works find when I run the transformation from XML file and
XSL file locate on the hard disk.

When I run the transformation against XML which generate on the fly by
a program. The base-uri function return empty. From the implementation
point of view there is no base-uri for a XML which generated on the
fly.

Jingjun


2009/8/21 Mark Wilson <mark@xxxxxxxxxxxx>
>
> As always Ken, you are more than helpful.
> Thanks,
> Mark
>
> --------------------------------------------------
> From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>
> Sent: Thursday, August 20, 2009 6:27 PM
> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
> Subject: Re: [xsl] Getting the name the input data document
>
>> I just remembered that isn't the only way ... you can also use base-uri():
>>
>> t:\ftemp>xslt2 mark.xml mark.xsl
>>
>> Filename: file:/t:/ftemp/mark.xml
>> Alternate: file:/t:/ftemp/mark.xml
>> t:\ftemp>type mark.xsl
>> <?xml version="1.0" encoding="US-ASCII"?>
>> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>>                version="2.0">
>>
>> <xsl:output method="text"/>
>>
>> <xsl:template match="/">
>> Filename: <xsl:value-of select="document-uri(/)"/>
>> Alternate: <xsl:value-of select="base-uri(/)"/>
>> </xsl:template>
>>
>> </xsl:stylesheet>
>> t:\ftemp>
>>
>>
>> At 2009-08-20 21:22 -0400, I wrote:
>>>
>>> At 2009-08-20 18:18 -0700, Mark Wilson wrote:
>>>>
>>>> I've poked around, but suspect I am searching for the wrong terms in the
index to Michael's XML/XPath book. I found one reference on the web that said
what I want to do could not be done with XSLT 1.0.
>>>
>>> You can do it for the stylesheet in XSLT 1.0 but not for the data file.
>>>
>>>> However, I am using XSLT 2.0.
>>>
>>> Not a problem.
>>>
>>>> I need to know the file name of the file my XSLT style sheet is acting
upon so that I can write it out as part of the tile of an XSL-FO output PDF
document. Does XSLT 2.0 have a way of getting the file name?
>>>
>>> The document-uri() function is what you need.
>>>
>>> I hope the example below helps.
>>>
>>> . . . . . . . . Ken
>>>
>>> t:\ftemp>xslt2 mark.xml mark.xsl
>>>
>>> Filename: file:/t:/ftemp/mark.xml
>>> t:\ftemp>type mark.xsl
>>> <?xml version="1.0" encoding="US-ASCII"?>
>>> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>>>                version="2.0">
>>>
>>> <xsl:output method="text"/>
>>>
>>> <xsl:template match="/">
>>> Filename: <xsl:value-of select="document-uri(/)"/>
>>> </xsl:template>
>>>
>>> </xsl:stylesheet>
>>> t:\ftemp>
>>
>>
>> --
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