Subject: Re: [xsl] Some attribute not displayed in output From: ac <ac@xxxxxxxxxxxxx> Date: Fri, 28 Aug 2009 10:43:15 -0400 |
Cheers, ac
Thanks ac. The </header> is a copy and paste error; it should be </Info> instead.
I had another problem which need help.
src.xml ----------- <info> <user id="123" /> <Product Category="A" /> <Product Category="B" /> <!-- a lot of other element .......--> </info>
Expected output ------------------------ <o t="info"> <a n="user"> <o t="user"> <a n="id"> <v s="123"> </a> </o> </a> <a n="Product"> <o t="Prodcut"> <a n="Category"> <v s="A"> </a> </o> <o t="Product"> <a n="Category"> <v s="B"> </a> </o> </a> </o>
Stylesheet ---------------- So basically for each element that found in src file, we should write it in following format <a n="element name"> <o t="element name"> </o> </a>
But when two similar element found, such as "Product", we should write it as below: <a n="element name"> <o t="element name"> </o> <o t="element name"> </o> </a>
My stylesheet below only works for single element:
<xsl:template match="*"> <a n="{name(.)}"> <o t="{name(.)}"> <xsl:for-each select="@*"> <a n="{name(.)}"> <xsl:element name="v"> <xsl:attribute name="s"> <xsl:value-of select="normalize-space(.)"/> </xsl:attribute> </xsl:element> </a> </xsl:for-each> <xsl:apply-templates/> </o> </a> </xsl:template>
How do I modify the stylesheet so that it can handle multiple element with the same name to match the expected output?
On Thu, Aug 27, 2009 at 11:45 AM, ac<ac@xxxxxxxxxxxxx> wrote:
Hi,
You could possibly simply add a template like
<xsl:template match="o[@t='Info']"> <xsl:element name="{@t}"> <xsl:apply-templates select="a[(@n!='Info') and (@n!='Sender')]"/> <xsl:apply-templates select="a[(@n='Info') or (@n='Sender')]"/> </xsl:element> </xsl:template>
which would ensure that attributes are processed first.
But I can not see where the </Header> in your output comes from.
Cheers, ac
I had following src xml file which needs to convert to the output.xml given below. I found some of the attributes ("MissingAttribute" in example given below) is not written to the output.xml with the stylesheet given. I check the spec and found that adding attribute after child node is added is illegal.
Can someone help me on how to modify the stylesheet to get the expected output (where "MissingAttribute" appeared as a attribute of Header element)?
src.xml (simplied version, the actual src files had many 'a' element) ----------- <?xml version="1.0" encoding="UTF-8"?> <data> <o t="request"> <a n="Info"> <o t="Info"> <a n="TimeStamp"> <v s="2009-08-81 12:59:59"/> </a> <a n="Sender"> <o t="Sender"> <a n="Login"> <v s="username"/> </a> </o> </a> <a n="MissingAttribute"> <v s="xxx"/> </a> </o> </a> </o> </data>
output.xml ---------------- <?xml version="1.0" encoding="utf-8"?> <request> <Info TimeStamp="2009-08-81 12:59:59" MissingAttribute="xxx"> <Sender Login="username"/> </Header> </request>
Stylesheet ---------------- <xsl:template match="o"> <xsl:element name="{@t}"> <xsl:apply-templates select="a"/> </xsl:element> </xsl:template>
<xsl:template match="a"> <xsl:if test="(@n!='Info') and (@n!='Sender') "> <xsl:attribute name="{@n}"> <xsl:for-each select="v"> <xsl:value-of select="@s"/> </xsl:for-each> </xsl:attribute> </xsl:if> <xsl:if test="(@n='Info') or (@n='Sender') "> <xsl:apply-templates select="o"/> </xsl:if> </xsl:template>
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