Re: [xsl] passing a regex matched substring to the result-document

[Martin Honnen <Martin.Honnen@xxxxxx>]

Manuel Souto Pico wrote:

> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; 
> version="2.0">
>    <xsl:output method="xml" encoding="UTF-16" standalone="no" name="xml" 
> indent="yes"/>
>    <xsl:strip-space elements="*" />
>    <xsl:template match="/">
>              <xsl:param name="COMMON"/>                    <xsl:for-each 
> select="//file">
>                      <xsl:variable name="srcfilename" 
> select="base-uri(/)"/>
>            <xsl:analyze-string select="$srcfilename" 
> regex=".+/([^/]+)\.(XLF|xlf)">
>                <xsl:matching-substring>
>                    <xsl:variable name="COMMON" select="regex-group(1)"/>
>                    <xsl:value-of select="$COMMON" /> <!-- Creating?? -->
>                </xsl:matching-substring>
>            </xsl:analyze-string>

I think you want
   <xsl:variable name="common">
           <xsl:analyze-string select="$srcfilename" 
regex=".+/([^/]+)\.(XLF|xlf)">
               <xsl:matching-substring>
                   <xsl:value-of select="regex-group(1)"/>
               </xsl:matching-substring>
           </xsl:analyze-string>
   </xsl:variable>
to store the matched group in the variable named common.

Then you can use that variable in e.g.

>                      <xsl:variable name="newfilename"
>                
> select="concat('output1/',$COMMON,_,@target-language,'.xlf')" />

  select="concat('output1/', $common, @target_language, '.xlf')"/>



--

	Martin Honnen
	http://msmvps.com/blogs/martin_honnen/