Re: [xsl] Generate a list of declared namespaces

["G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>]

At 2009-11-12 00:42 +0000, Anders Viklund wrote:
> I would like to generate a list of declared namespaces for an xml file.
>
> Any ideas how I can do this?

Use the namespace axis.  You have to search the entire document in 
case you have namespaces declared below the document element.

I hope the example below helps.

. . . . . . . Ken

t:\ftemp>xslt anders.xsl anders.xsl
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:anders="urn:X-Anders"

t:\ftemp>type anders.xsl
<?xml version="1.0" encoding="US-ASCII"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
                version="1.0">

<xsl:output method="text"/>

<xsl:variable name="ns" select="//namespace::*[name(.)!='xml']"/>

<xsl:template match="/" xmlns:anders="urn:X-Anders">
  <xsl:for-each select="$ns">
    <xsl:if test="generate-id(.)=
                  generate-id($ns[name(.)=name(current())][1])">
    <xsl:value-of select="concat('xmlns:',name(.),'=&#x22;',.,'&#x22;')"/>
    <xsl:text>
</xsl:text>
    </xsl:if>
  </xsl:for-each>
</xsl:template>

</xsl:stylesheet>

t:\ftemp>

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