Subject: Re: [xsl] sort a node across a dynamic group of files From: Martin Honnen <Martin.Honnen@xxxxxx> Date: Sun, 22 Nov 2009 20:51:32 +0100 |
Thank you for any help you can give on this matter. I appreciate any and all leads. I hope I haven't left any relevant information out.
<toc> <file>0001.xml</file> <file>0002.xml</file> <file>0003.xml</file> </toc>
<xsl:template match="toc"> <xsl:for-each select="document(file)/entry"> <xsl:sort .../> </xsl:for-each> </xsl:template>
Martin Honnen http://msmvps.com/blogs/martin_honnen/
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