Re: [xsl] Transforming xml with any namespace

Subject: Re: [xsl] Transforming xml with any namespace
From: Florent Georges <lists@xxxxxxxxxxxx>
Date: Wed, 25 Nov 2009 14:25:11 +0000 (GMT)
Anders Viklund wrote:

> <xsl:template match="//*[local-name()='Type1']">
You can use the XPath 2.0 namespace wildcard:

    <xsl:template
match="*:Type1">

-- 
Florent Georges
http://www.fgeorges..org/

Current Thread