[xsl] Trying to understand XSLT processing

Subject: [xsl] Trying to understand XSLT processing
From: <ohaya@xxxxxxx>
Date: Mon, 14 Dec 2009 21:34:59 -0500
Hi,

I have an XML file:

<SOAP:Envelope xmlns:saml="urn:oasis:names:tc:SAML:1.0:assertion" xmlns:samlp="urn:oasis:names:tc:SAML:1.0:protocol" xmlns:SOAP="http://schemas.xmlsoap.org/soap/envelope/"; xmlns:wsse="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd"; xmlns:env="http://schemas.xmlsoap.org/soap/envelope/";>
    <SOAP:Header>
        <wsse:Security SOAP:mustUnderstand="1">
        </wsse:Security></SOAP:Header>
    <SOAP:Body>
        <m:hello xmlns:m="http://services";>
            <m:x>123</m:x>
        </m:hello>
    </SOAP:Body>
</SOAP:Envelope>

and I just want to output the <SOAP:Body> to a message, so I have an XSLT that looks like this:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";        
    xmlns:SOAP="http://www.w3.org/2003/05/soap-envelope";
    xmlns:soapenv="http://www.w3.org/2003/05/soap-envelope";>
    <xsl:output method="xml" /> 
    
    <xsl:template match="/">
        <xsl:message>*****you just hit the XSLT ******</xsl:message>
        <xsl:message>*****BODY CONTENTS****[<xsl:copy-of select="."/>]</xsl:message>
    </xsl:template>
    
</xsl:stylesheet>

However, when I execute that XSLT, I'm getting an empty nodeset for the output:

*****you just hit the XSLT ******
*****BODY CONTENTS****[]

So, I was wondering if someone can explain what I am doing wrong with that XSLT above?  Why doesn't the <xsl:copy-of> give me the <Body>?

Thanks, and sorry if this is probably a really dumb question :(...

Jim

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