Subject: [xsl] Trying to understand XSLT processing From: <ohaya@xxxxxxx> Date: Mon, 14 Dec 2009 21:34:59 -0500 |
Hi, I have an XML file: <SOAP:Envelope xmlns:saml="urn:oasis:names:tc:SAML:1.0:assertion" xmlns:samlp="urn:oasis:names:tc:SAML:1.0:protocol" xmlns:SOAP="http://schemas.xmlsoap.org/soap/envelope/" xmlns:wsse="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd" xmlns:env="http://schemas.xmlsoap.org/soap/envelope/"> <SOAP:Header> <wsse:Security SOAP:mustUnderstand="1"> </wsse:Security></SOAP:Header> <SOAP:Body> <m:hello xmlns:m="http://services"> <m:x>123</m:x> </m:hello> </SOAP:Body> </SOAP:Envelope> and I just want to output the <SOAP:Body> to a message, so I have an XSLT that looks like this: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:SOAP="http://www.w3.org/2003/05/soap-envelope" xmlns:soapenv="http://www.w3.org/2003/05/soap-envelope"> <xsl:output method="xml" /> <xsl:template match="/"> <xsl:message>*****you just hit the XSLT ******</xsl:message> <xsl:message>*****BODY CONTENTS****[<xsl:copy-of select="."/>]</xsl:message> </xsl:template> </xsl:stylesheet> However, when I execute that XSLT, I'm getting an empty nodeset for the output: *****you just hit the XSLT ****** *****BODY CONTENTS****[] So, I was wondering if someone can explain what I am doing wrong with that XSLT above? Why doesn't the <xsl:copy-of> give me the <Body>? Thanks, and sorry if this is probably a really dumb question :(... Jim
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